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##(一)题目
Given a string, determine if it is a palindrome, considering only alphanumeric characters and ignoring cases.
For example, "A man, a plan, a canal: Panama" is a palindrome. "race a car" is not a palindrome.
Note: Have you consider that the string might be empty? This is a good question to ask during an interview.
For the purpose of this problem, we define empty string as valid palindrome.
##(二)解题
题目大意:判断一个字符串是不是有效的回文字符串。忽略里面除了数字和字母的其他字符。
解题思路:两个指针i和j,i从前往后,j从后往前,碰到p[i]和p[j]都是字母或者数字就比较大小,如果相等就i++,j--反之则返回false
直到i>=j时,说明是有效回文,返回true。
class Solution {
public:
bool isPalindrome(string s) {
int len = s.length();
int i = 0;
int j = len-1;
while(i<=j)
{
while(!isalnum(s[i])&&i<=j) i++;//直到s[i]为字母或数字为止
while(!isalnum(s[j])&&i<=j) j--;//直到s[j]为字母或数字为止
if(i<=j&&tolower(s[i])!=tolower(s[j])) return false;//如果不等就返回false
i++;j--;//反之就继续比较
}
return true;
}
};