From 01c3d750d20e86c7aff7d0df8b017f82bef9b3de Mon Sep 17 00:00:00 2001
From: 0xff-dev <stevenshuang521@gmail.com>
Date: Wed, 4 Dec 2024 09:26:21 +0800
Subject: [PATCH] Add solution and test-cases for problem 2825

---
 .../README.md                                 | 47 +++++++++++++++++++
 .../Solution.go                               | 15 +++++-
 .../Solution_test.go                          | 18 +++----
 3 files changed, 69 insertions(+), 11 deletions(-)
 create mode 100644 leetcode/2801-2900/2825.Make-String-a-Subsequence-Using-Cyclic-Increments/README.md

diff --git a/leetcode/2801-2900/2825.Make-String-a-Subsequence-Using-Cyclic-Increments/README.md b/leetcode/2801-2900/2825.Make-String-a-Subsequence-Using-Cyclic-Increments/README.md
new file mode 100644
index 000000000..46397a55b
--- /dev/null
+++ b/leetcode/2801-2900/2825.Make-String-a-Subsequence-Using-Cyclic-Increments/README.md
@@ -0,0 +1,47 @@
+# [2825.Make String a Subsequence Using Cyclic Increments][title]
+
+## Description
+You are given two **0-indexed** strings `str1` and `str2`.
+
+In an operation, you select a **set** of indices in `str1`, and for each index `i` in the set, increment `str1[i]` to the next character **cyclically**. That is `'a'` becomes `'b'`, `'b'` becomes `'c'`, and so on, and `'z'` becomes `'a'`.
+
+Return `true` if it is possible to make `str2` a subsequence of `str1` by performing the operation **at most once**, and `false` otherwise.
+
+**Note**: A subsequence of a string is a new string that is formed from the original string by deleting some (possibly none) of the characters without disturbing the relative positions of the remaining characters.
+
+**Example 1:**
+
+```
+Input: str1 = "abc", str2 = "ad"
+Output: true
+Explanation: Select index 2 in str1.
+Increment str1[2] to become 'd'. 
+Hence, str1 becomes "abd" and str2 is now a subsequence. Therefore, true is returned.
+```
+
+**Example 2:**
+
+```
+Input: str1 = "zc", str2 = "ad"
+Output: true
+Explanation: Select indices 0 and 1 in str1. 
+Increment str1[0] to become 'a'. 
+Increment str1[1] to become 'd'. 
+Hence, str1 becomes "ad" and str2 is now a subsequence. Therefore, true is returned.
+```
+
+**Example 3:**
+
+```
+Input: str1 = "ab", str2 = "d"
+Output: false
+Explanation: In this example, it can be shown that it is impossible to make str2 a subsequence of str1 using the operation at most once. 
+Therefore, false is returned.
+```
+
+## 结语
+
+如果你同我一样热爱数据结构、算法、LeetCode，可以关注我 GitHub 上的 LeetCode 题解：[awesome-golang-algorithm][me]
+
+[title]: https://leetcode.com/problems/make-string-a-subsequence-using-cyclic-increments
+[me]: https://github.com/kylesliu/awesome-golang-algorithm
diff --git a/leetcode/2801-2900/2825.Make-String-a-Subsequence-Using-Cyclic-Increments/Solution.go b/leetcode/2801-2900/2825.Make-String-a-Subsequence-Using-Cyclic-Increments/Solution.go
index d115ccf5e..f72c9780b 100755
--- a/leetcode/2801-2900/2825.Make-String-a-Subsequence-Using-Cyclic-Increments/Solution.go
+++ b/leetcode/2801-2900/2825.Make-String-a-Subsequence-Using-Cyclic-Increments/Solution.go
@@ -1,5 +1,16 @@
 package Solution
 
-func Solution(x bool) bool {
-	return x
+func Solution(str1 string, str2 string) bool {
+	if len(str2) > len(str1) {
+		return false
+	}
+	b := 0
+	for i := 0; i < len(str1) && b < len(str2); i++ {
+		t1 := str1[i] - 'a'
+		t2 := str2[b] - 'a'
+		if t1 == t2 || t2 == (t1+1+26)%26 {
+			b++
+		}
+	}
+	return b == len(str2)
 }
diff --git a/leetcode/2801-2900/2825.Make-String-a-Subsequence-Using-Cyclic-Increments/Solution_test.go b/leetcode/2801-2900/2825.Make-String-a-Subsequence-Using-Cyclic-Increments/Solution_test.go
index 14ff50eb4..01a9ad107 100755
--- a/leetcode/2801-2900/2825.Make-String-a-Subsequence-Using-Cyclic-Increments/Solution_test.go
+++ b/leetcode/2801-2900/2825.Make-String-a-Subsequence-Using-Cyclic-Increments/Solution_test.go
@@ -10,30 +10,30 @@ func TestSolution(t *testing.T) {
 	//	测试用例
 	cases := []struct {
 		name   string
-		inputs bool
+		s1, s2 string
 		expect bool
 	}{
-		{"TestCase", true, true},
-		{"TestCase", true, true},
-		{"TestCase", false, false},
+		{"TestCase1", "abc", "ad", true},
+		{"TestCase2", "zc", "ad", true},
+		{"TestCase3", "ab", "d", false},
 	}
 
 	//	开始测试
 	for i, c := range cases {
 		t.Run(c.name+" "+strconv.Itoa(i), func(t *testing.T) {
-			got := Solution(c.inputs)
+			got := Solution(c.s1, c.s2)
 			if !reflect.DeepEqual(got, c.expect) {
-				t.Fatalf("expected: %v, but got: %v, with inputs: %v",
-					c.expect, got, c.inputs)
+				t.Fatalf("expected: %v, but got: %v, with inputs: %v %v",
+					c.expect, got, c.s1, c.s2)
 			}
 		})
 	}
 }
 
-//	压力测试
+// 压力测试
 func BenchmarkSolution(b *testing.B) {
 }
 
-//	使用案列
+// 使用案列
 func ExampleSolution() {
 }