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10. Regular Expression Matching.js
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10. Regular Expression Matching.js
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/**
* Implement regular expression matching with support for '.' and '*'.
*/
/**
* '.' Matches any single character.
* '*' Matches zero or more of the preceding element.
* The matching should cover the entire input string (not partial).
* The function prototype should be:
* bool isMatch(const char *s, const char *p)
* Some examples:
* isMatch("aa","a") → false
* isMatch("aa","aa") → true
* isMatch("aaa","aa") → false
* isMatch("aa", "a*") → true
* isMatch("aa", ".*") → true
* isMatch("ab", ".*") → true
* isMatch("aab", "c*a*b") → true
*/
/**
* @param {string} s
* @param {string} p
* @return {boolean}
*/
var isMatch = function(s, p) {
if (s.length > 0 && p.length === 0) {
return false;
}
const dp = [[true]];
for (let i = 0; i < p.length; i++) {
dp[0][i + 1] = p.charAt(i) === '*' && dp[0][i - 1];
}
for (let i = 0; i < s.length; i++) {
for (let j = 0; j < p.length; j++) {
if (dp[i + 1] === undefined) {
dp[i + 1] = [];
}
if (p.charAt(j) === '.' || p.charAt(j) === s.charAt(i)) {
dp[i + 1][j + 1] = dp[i][j];
}
if (p.charAt(j) === '*') {
if (p.charAt(j - 1) !== s.charAt(i) && p.charAt(j - 1) !== '.') {
dp[i + 1][j + 1] = dp[i + 1][j - 1];
} else {
dp[i + 1][j + 1] = (dp[i + 1][j] || dp[i][j + 1] || dp[i + 1][j - 1]);
}
}
}
}
return dp[s.length][p.length] === undefined ? false : dp[s.length][p.length];
};
console.log(isMatch("a", ""));
console.log(isMatch("aa", "a"));
console.log(isMatch("ab", ".*"));
console.log(isMatch("aab", "c*a*b"));
console.log(isMatch("aaa", "aaaa"));
console.log(isMatch("", ".*"));
console.log(isMatch("", ""));