Need help! I am stuck on this. Find the user who has many skills.

[axad1]

const txt = { "Alex": { "email": "alex@alex.com", "skills": [ "HTML", "CSS", "JavaScript" ], "age": 20, "isLoggedIn": false, "points": 30 }, "Asab": { "email": "asab@asab.com", "skills": [ "HTML", "CSS", "JavaScript", "Redux", "MongoDB", "Express", "React", "Node" ], "age": 25, "isLoggedIn": false, "points": 50 }, }

[dnthem]

I think what the question asks is to find the person who has the most skills.

let max = Number.MIN_SAFE_INTEGER;
let res = undefined;
for (const key in users)
{
     const user = users[key];
     if (user.skills.length > max)
    {
         max = user.skills.length;
         res = user;
     }
}

[palamarchukser]

Hey @AsadHusn , is this solution right for you?

const txt = { "Alex": { "email": "alex@alex.com", "skills": [ "HTML", "CSS", "JavaScript" ], "age": 20, "isLoggedIn": false, "points": 30 }, "Asab": { "email": "asab@asab.com", "skills": [ "HTML", "CSS", "JavaScript", "Redux", "MongoDB", "Express", "React", "Node" ], "age": 25, "isLoggedIn": false, "points": 50 }, };

let result = Object.keys(txt).reduce((a, b) => (txt[a].skills.length > txt[b].skills.length) ? a : b);

console.log(result) // For getting Username who has many skills
console.log(txt[result]) // For getting User object who has many skills

[Vamsi3prog]

const txt = { "Alex": { "email": "alex@alex.com", "skills": [ "HTML", "CSS", "JavaScript" ], "age": 20, "isLoggedIn": false, "points": 30 }, "Asab": { "email": "asab@asab.com", "skills": [ "HTML", "CSS", "JavaScript", "Redux", "MongoDB", "Express", "React", "Node" ], "age": 25, "isLoggedIn": false, "points": 50 }, }
if (txt.Alex.skills.length > txt.Asab.skills.length) {
console.log("Alex has more skills (" + txt.Alex.skills + ")");
} else {
console.log("Asab has more skills (" + txt.Alex.skills + ")");
}

[JohnArbie]

function getMostskill() {
let max = 1
let maxSkill = {}
for (const key in users) {
const user = users[key]
if(user.skills.length > max){
maxSkill = user
max = user.skills.length
}
}
return maxSkill
}