-
Notifications
You must be signed in to change notification settings - Fork 74
/
count_distinct_slices.py
75 lines (56 loc) · 2.04 KB
/
count_distinct_slices.py
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
"""
An integer M and a non-empty zero-indexed array A consisting of N non-negative
integers are given. All integers in array A are less than or equal to M.
A pair of integers (P, Q), such that 0 ≤ P ≤ Q < N, is called a slice of array A.
The slice consists of the elements A[P], A[P + 1], ..., A[Q].
A distinct slice is a slice consisting of only unique numbers.
That is, no individual number occurs more than once in the slice.
For example, consider integer M = 6 and array A such that:
A[0] = 3
A[1] = 4
A[2] = 5
A[3] = 5
A[4] = 2
There are exactly nine distinct slices:
(0, 0), (0, 1), (0, 2), (1, 1), (1, 2), (2, 2), (3, 3), (3, 4) and (4, 4).
The goal is to calculate the number of distinct slices.
Write a function:
def solution(M, A)
that, given an integer M and a non-empty zero-indexed array A consisting of N integers,
returns the number of distinct slices.
If the number of distinct slices is greater than 1,000,000,000,
the function should return 1,000,000,000.
For example, given integer M = 6 and array A such that:
A[0] = 3
A[1] = 4
A[2] = 5
A[3] = 5
A[4] = 2
the function should return 9, as explained above.
Assume that:
N is an integer within the range [1..100,000];
M is an integer within the range [0..100,000];
each element of array A is an integer within the range [0..M].
Complexity:
expected worst-case time complexity is O(N);
expected worst-case space complexity is O(M),
beyond input storage (not counting the storage required for input arguments).
Elements of input arrays can be modified.
"""
def solution(M, A):
N = len(A)
last = 0
result = 0
s = [-1] * (M + 1)
for i, a in enumerate(A):
if s[a] >= last:
result += (i - last) * (i - last + 1) // 2
last = s[a] + 1
result -= (i - last) * (i - last + 1) // 2
if result > 1e9:
return int(1e9)
s[a] = i
result += (N - last) * (N - last + 1) // 2
if result > 1e9:
return int(1e9)
return result