Given an integer array nums
and an integer k
, return true
if there are two distinct indices i
and j
in the array such that nums[i] == nums[j]
and abs(i - j) <= k
.
Example 1:
Input: nums = [1,2,3,1], k = 3 Output: true
Example 2:
Input: nums = [1,0,1,1], k = 1 Output: true
Example 3:
Input: nums = [1,2,3,1,2,3], k = 2 Output: false
Constraints:
1 <= nums.length <= 105
-109 <= nums[i] <= 109
0 <= k <= 105
class Solution:
def containsNearbyDuplicate(self, nums: List[int], k: int) -> bool:
helper = {}
for i, v in enumerate(nums):
if v in helper and i - helper[v] <= k:
return True
helper[v] = i
return False
class Solution {
public boolean containsNearbyDuplicate(int[] nums, int k) {
Map<Integer, Integer> helper = new HashMap<>();
for (int i = 0, n = nums.length; i < n; ++i) {
if (helper.containsKey(nums[i])) {
int j = helper.get(nums[i]);
if (i - j <= k) {
return true;
}
}
helper.put(nums[i], i);
}
return false;
}
}