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412. Fizz Buzz

English Version

题目描述

写一个程序，输出从 1 到 n 数字的字符串表示。

1. 如果 n 是3的倍数，输出“Fizz”；

2. 如果 n 是5的倍数，输出“Buzz”；

3.如果 n 同时是3和5的倍数，输出 “FizzBuzz”。

示例：

n = 15,

返回:
[
    "1",
    "2",
    "Fizz",
    "4",
    "Buzz",
    "Fizz",
    "7",
    "8",
    "Fizz",
    "Buzz",
    "11",
    "Fizz",
    "13",
    "14",
    "FizzBuzz"
]

解法

Python3

class Solution:
    def fizzBuzz(self, n: int) -> List[str]:
        ans = []
        for i in range(1, n + 1):
            if i % 15 == 0:
                ans.append('FizzBuzz')
            elif i % 3 == 0:
                ans.append('Fizz')
            elif i % 5 == 0:
                ans.append('Buzz')
            else:
                ans.append(str(i))
        return ans

Java

class Solution {
    public List<String> fizzBuzz(int n) {
        List<String> ans = new ArrayList<>();
        for (int i = 1; i <= n; ++i) {
            String s = "";
            if (i % 3 == 0) {
                s += "Fizz";
            }
            if (i % 5 == 0) {
                s += "Buzz";
            }
            if (s.length() == 0) {
                s += i;
            }
            ans.add(s);
        }
        return ans;
    }
}

C++

class Solution {
public:
    vector<string> fizzBuzz(int n) {
        vector<string> ans;
        for (int i = 1; i <= n; ++i)
        {
            string s = "";
            if (i % 3 == 0) s += "Fizz";
            if (i % 5 == 0) s += "Buzz";
            if (s.size() == 0) s = to_string(i);
            ans.push_back(s);
        }
        return ans;
    }
};

Go

func fizzBuzz(n int) []string {
	var ans []string
	for i := 1; i <= n; i++ {
		s := &strings.Builder{}
		if i%3 == 0 {
			s.WriteString("Fizz")
		}
		if i%5 == 0 {
			s.WriteString("Buzz")
		}
		if s.Len() == 0 {
			s.WriteString(strconv.Itoa(i))
		}
		ans = append(ans, s.String())
	}
	return ans
}

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