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As can be seen, the combination that doesn't exist are benign when V1= 9 and 10, is it possible to use by function to append 0 if the combination doesn't exists?
Thanks.
The text was updated successfully, but these errors were encountered:
This is duplilcate of #2106 so I will close this issue (if you feel that something should be added can you please comment there?).
For the time being you can do the following as a half-measure (you will get missing instead of 0 in the target column but it can be easily fixed with coalesce):
Hi,
I would like to do group by count on every possible combination between 2 columns using
by
as below.As can be seen, the combination that doesn't exist are benign when V1= 9 and 10, is it possible to use
by
function to append 0 if the combination doesn't exists?Thanks.
The text was updated successfully, but these errors were encountered: