https://leetcode.com/problems/deepest-leaves-sum/
Given the root
of a binary tree, return the sum of values of its deepest leaves.
Example 1:
Input: root = [1,2,3,4,5,null,6,7,null,null,null,null,8]
Output: 15
Example 2:
Input: root = [6,7,8,2,7,1,3,9,null,1,4,null,null,null,5]
Output: 19
Constraints:
- The number of nodes in the tree is in the range
[1, 104]
. 1 <= Node.val <= 100
BFS
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode() {}
* TreeNode(int val) { this.val = val; }
* TreeNode(int val, TreeNode left, TreeNode right) {
* this.val = val;
* this.left = left;
* this.right = right;
* }
* }
*/
class Solution {
// bfs
public int deepestLeavesSum(TreeNode root) {
int res = 0;
Deque<TreeNode> queue = new ArrayDeque<>();
queue.add(root);
while (!queue.isEmpty()) {
int size = queue.size();
int cur = 0;
for (int i = 0; i < size; i++) {
TreeNode node = queue.poll();
cur += node.val;
if (node.left != null) queue.add(node.left);
if (node.right != null) queue.add(node.right);
}
res = cur;
}
return res;
}
}