https://leetcode.com/problems/simplify-path/
Given an absolute path for a file (Unix-style), simplify it. Or in other words, convert it to the canonical path.
In a UNIX-style file system, a period '.'
refers to the current directory. Furthermore, a double period '..'
moves the directory up a level.
Note that the returned canonical path must always begin with a slash '/'
, and there must be only a single slash '/'
between two directory names. The last directory name (if it exists) must not end with a trailing '/'
. Also, the canonical path must be the shortest string representing the absolute path.
Example 1:
Input: path = "/home/"
Output: "/home"
Explanation: Note that there is no trailing slash after the last directory name.
Example 2:
Input: path = "/../"
Output: "/"
Explanation: Going one level up from the root directory is a no-op, as the root level is the highest level you can go.
Example 3:
Input: path = "/home//foo/"
Output: "/home/foo"
Explanation: In the canonical path, multiple consecutive slashes are replaced by a single one.
Example 4:
Input: path = "/a/./b/../../c/"
Output: "/c"
Constraints:
1 <= path.length <= 3000
path
consists of English letters, digits, period'.'
, slash'/'
or'_'
.path
is a valid Unix path.
- Using stack
class Solution(object):
def simplifyPath(self, path):
stack = []
for p in path.split("/"):
if p == "..":
if stack:
stack.pop()
elif p == "." or not p:
continue
else:
stack.append(p)
res = "/" + "/".join(stack)
return res