How do I get the class name from a PyRef<Self>

[samuelcolvin]

If I have a type that implements, #[pyclass(subclass..., and I call a method on that "class", is it possible to get the name of the class on which that method was called in the method?

The rust equivalent of

class BaseClass:
    def foobar(self):
        print(self.__class__.__name__)  # < how do I do this?

class ChildClass(BaseClass):
    pass

c = ChildClass()
c.foobar()
#> ChildClass

[birkenfeld]

You can take self as PyCell<BaseClass>, which is still usable as a PyAny. Take this Rust module:

use pyo3::prelude::*;

#[pyclass(subclass)]
pub struct Base;

#[pymethods]
impl Base {
    #[new]
    pub fn new() -> Self { Self }

    fn which(slf: &PyCell<Self>) -> PyResult<&str> {
        slf.get_type().name()
    }
}

#[pymodule]
fn o3(py: Python<'_>, m: &PyModule) -> PyResult<()> {
    m.add_class::<Base>()
}

and this Python code:

from o3 import Base

class Sub(Base):
    pass

print(Base().which())
print(Sub().which())

it will print

Base
Sub