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parser implementation notes
- Alphabet = Token
- Grammar rules are stored in a file
- Non-terminals are stored without
<>
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->
is omitted from rules- It is clear that first string is LHS and rest is RHS
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Handle Nullable non-terminals
- will help to calculate follow sets
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Enumerate non-terminals also so that
FIRST[statements]
can be implemented since array indices should be integers.typedef enum {statements, index, expression, ....} nonterminals
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Structure of
mapping table
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String Enumerated value FLAG "statement" STATEMENT NT "switch" SWITCH T -
String => What I am reading from file
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Flag => terminals or nonterminals
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Enumerated value =>
typedef union{ terminal t; non_terminal nt; } symbol;
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typedef struct{ symbol s; char str[MAX_LEXEME_LEN]; int tag; //terminal or non-terminal } mapping table[SIZE]; //SIZE is number of terminals + non-terminals
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But since implementation will be in form of a hash table, keep size as a
prime number
near to actual value of SIZE.
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RHS of any production is not of fixed length so should be implemented as a linked list
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So set of productions will be implemented as an array of linked lists
- instead of linked list of linked lists, prefer array of linked lists
- will help in random access
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structure for linked list node for RHS
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typedef enum {T, NT} type_of_sym; struct rhsnode{ symbol s; type_of_sym flag; struct rhsnode *next; }; typedef struct rhsnode RHSNODE;
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structure for LHS
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typedef struct cell{ nonterminal sym; RHSNODE *head; } GRAMMAR[ NUM_OF_RULES ];
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Grammar is an array of cells
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Doing
GRAMMAR G;
allocates memory -- static memory allocation -
To get Dynamic memory allocation ( on heap ), define GRAMMAR as
*GRAMMAR
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PARSE TABLE
- Rows are non-terminals
- Columns are terminals
- Entries are Rules
- So keep an
2d array of pointers
, pointing to rule's head node
- Implementing FIRST set.
- Symbols are enumerated now.
- Union is required to be done in O(1) time
- Use Bit masks
- So say FIRST(A) = {a}
- Write it as
FIRST[A] = 0; //Initialize as an empty set
mask = 1;
FIRST[A] |= (mask << a);
- It works because A and a (terminals and nonterminals) are enumerated
- I will also need the
positions set as 1
becuase I will need what elements are there in the FIRST set.
- One of nonterminals
- Done above
- RHS of a rule
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A -> aBcd
andA -> DE
, both rules go in some other colums in the parse table
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Predective, top-down parser
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Table driven
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Table creation done
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Algo
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Stack implementation
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push(stk, S)
- push start symbol on Stack -
while(){ check top; if top(stk) is a terminal{ match with lookahead character from lexer if(match found){ get_next_token(): } } else if(nonterminal) { // say NT is "A" // and lookahead character is "a" check table T[A][a] if( there exists a valid rule){ pop off top of stack; push rule's RHS on to stack. } } }
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While pushing on stack, care is to be taken to make parse tree successfully
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Parse tree structure
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trie - number of children aren't fixed, so dynamically allocate memort
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need to use an auxilliary stack for the purpose
- A -> BCD, needs to push D, C , followed by B on main stack
- but node addition to trie is done in manner of B, C, followed by D.
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Main stack stores our PDA
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