-
Notifications
You must be signed in to change notification settings - Fork 0
/
Day15_SortColors.cpp
63 lines (44 loc) · 1.23 KB
/
Day15_SortColors.cpp
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
// Given an array nums with n objects colored red, white, or blue, sort them in-place so that objects of the same color are adjacent, with the colors in the order red, white, and blue.
// We will use the integers 0, 1, and 2 to represent the color red, white, and blue, respectively.
// You must solve this problem without using the library's sort function.
// Example 1:
// Input: nums = [2,0,2,1,1,0]
// Output: [0,0,1,1,2,2]
// Example 2:
// Input: nums = [2,0,1]
// Output: [0,1,2]
// Constraints:
// n == nums.length
// 1 <= n <= 300
// nums[i] is either 0, 1, or 2.
// Follow up: Could you come up with a one-pass algorithm using only constant extra space?
// Topics
// Array
// Two Pointers
// Sorting
// Solutions:
class Solution {
public:
void sortColors(vector<int>& nums) {
int n=nums.size();
int zero=0,one=0,two=0;
for(int i=0;i<n;i++){
if(nums[i]==0){zero++;}
else if(nums[i]==1){one++;}
else{two++;}
}
int i=0;
while(zero-->0){
nums[i]=0;
i++;
}
while(one-->0){
nums[i]=1;
i++;
}
while(two-->0){
nums[i]=2;
i++;
}
}
};