A+B.xml

<?xml version="1.0" encoding="UTF-8"?>   
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	<item>
<title><![CDATA[送分题-A+B Problem]]></title>
<time_limit unit="s"><![CDATA[1]]></time_limit>
<memory_limit unit="mb"><![CDATA[256]]></memory_limit>

<description><![CDATA[<p>Calculate a+b</p>]]></description>
<input><![CDATA[<p>Two integer a,b (0&lt;=a,b&lt;=10)</p>]]></input> 
<output><![CDATA[<p>Output a+b</p>]]></output>
<sample_input><![CDATA[1 2]]></sample_input>
<sample_output><![CDATA[3]]></sample_output>
  <test_input><![CDATA[500 17]]></test_input>
<test_output><![CDATA[517]]></test_output>
<test_input><![CDATA[2 3
]]></test_input>
<test_output><![CDATA[5
]]></test_output>
<hint><![CDATA[<p>Q: Where are the input and the output? A: Your program shall always <font color="#ff0000">read input from stdin (Standard Input) and write output to stdout (Standard Output)</font>. For example, you can use 'scanf' in C or 'cin' in C++ to read from stdin, and use 'printf' in C or 'cout' in C++ to write to stdout. You <font color="#ff0000">shall not output any extra data</font> to standard output other than that required by the problem, otherwise you will get a &quot;Wrong Answer&quot;. User programs are not allowed to open and read from/write to files. You will get a &quot;Runtime Error&quot; or a &quot;Wrong Answer&quot; if you try to do so. Here is a sample solution for problem 1000 using C++/G++:</p>
<pre>
#include &lt;iostream&gt;
using namespace std;
int  main()
{
    int a,b;
    cin &gt;&gt; a &gt;&gt; b;
    cout &lt;&lt; a+b &lt;&lt; endl;
    return 0;
}</pre>
<p>It's important that the return type of main() must be int when you use G++/GCC,or you may get compile error. Here is a sample solution for problem 1000 using C/GCC:</p>
<pre>
#include &lt;stdio.h&gt;

int main()
{
    int a,b;
    scanf(&quot;%d %d&quot;,&amp;a, &amp;b);
    printf(&quot;%d\n&quot;,a+b);
    return 0;
}</pre>
<p>Here is a sample solution for problem 1000 using PASCAL:</p>
<pre>
program p1000(Input,Output); 
var 
  a,b:Integer; 
begin 
   Readln(a,b); 
   Writeln(a+b); 
end.</pre>
<p>Here is a sample solution for problem 1000 using JAVA: Now java compiler is jdk 1.5, next is program for 1000</p>
<pre>
import java.io.*;
import java.util.*;
public class Main
{
            public static void main(String args[]) throws Exception
            {
                    Scanner cin=new Scanner(System.in);
                    int a=cin.nextInt();
                    int b=cin.nextInt();
                    System.out.println(a+b);
            }
}</pre>
<p>Old program for jdk 1.4</p>
<pre>
import java.io.*;
import java.util.*;

public class Main
{
    public static void main (String args[]) throws Exception
    {
        BufferedReader stdin = 
            new BufferedReader(
                new InputStreamReader(System.in));

        String line = stdin.readLine();
        StringTokenizer st = new StringTokenizer(line);
        int a = Integer.parseInt(st.nextToken());
        int b = Integer.parseInt(st.nextToken());
        System.out.println(a+b);
    }
}</pre>]]></hint>
<source><![CDATA[系统原理，熟悉OJ]]></source>
		<solution language="C"><![CDATA[#include <stdio.h>
int main()
{
	int a,b;
	while(scanf("%d%d",&a,&b)!=EOF)
	{
		printf("%d\n",a+b);
	}
	return 0;
}]]></solution>
			<solution language="C++"><![CDATA[#include <iostream>
#include <cstdio>
using namespace std;
int main()
{
#ifndef ONLINE_JUDGE
	freopen("in.txt","r",stdin);
#endif
	int a,b;
	while(cin >>a >>b)
	{
		cout <<a+b <<endl;
	}
	return 0;
}]]></solution>
			<solution language="Pascal"><![CDATA[program abprob;
var
  a,b:longint;
begin
   readln(a,b);
   writeln(a+b);
end.]]></solution>
			<solution language="Java"><![CDATA[import java.util.*;
public class Main
{
	public static void main(String args[])
	{
		Scanner cin = new Scanner(System.in);
		int a,b;

		while(cin.hasNextInt())
		{
			a = cin.nextInt();
			b = cin.nextInt();
			System.out.println(a+b);
		}
	}
}]]></solution>
			<solution language="Bash"><![CDATA[read a b
let c=$a+$b
echo $c]]></solution>
			<solution language="Python"><![CDATA[#!/usr/bin/python2
a=raw_input() 
b=a.split(" ") 
print eval(b[0]+"+"+b[1]) 
]]></solution>
			<solution language="C#"><![CDATA[using System;
class Program {
    public static void Main() {
        string line;
        string []p;
        int a,b;
        while((line=Console.ReadLine())!=null){
            p=line.Split(' ');
            a=int.Parse(p[0]);b=int.Parse(p[1]);
            Console.WriteLine(a+b);
        }
    }
}]]></solution>
	</item>
</fps>