JavaIfElse.java

/*Java If Else 

In this challenge, we test your knowledge of using if-else conditional statements to automate decision-making processes. An if-else statement has the following logical flow:

Wikipedia if-else flow chart

Source: Wikipedia

Task
Given an integer, , perform the following conditional actions:

If  is odd, print Weird
If  is even and in the inclusive range of  to , print Not Weird
If  is even and in the inclusive range of  to , print Weird
If  is even and greater than , print Not Weird
Complete the stub code provided in your editor to print whether or not  is weird.

Input Format

A single line containing a positive integer, .

Constraints

Output Format

Print Weird if the number is weird; otherwise, print Not Weird.

Sample Input 0

3
Sample Output 0

Weird
Sample Input 1

24
Sample Output 1

Not Weird
Explanation

Sample Case 0: 
 is odd and odd numbers are weird, so we print Weird.

Sample Case 1: 
 and  is even, so it isn't weird. Thus, we print Not Weird.

 
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                                                                            Solution
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*/

import java.io.*;
import java.math.*;
import java.security.*;
import java.text.*;
import java.util.*;
import java.util.concurrent.*;
import java.util.regex.*;

public class JavaIfElse {

    public static void main(String[] args) {
    
       Scanner scanner = new Scanner(System.in);

        int N = scanner.nextInt();
        if(N==20 || N==18)
            {
                 System.out.println("Weird");
            }
        else if( N%2==0)
        { 
             System.out.println("Not Weird");
            for(int i=6;i>20;i++)
            {
                System.out.println("Weird");
            }
        }
                   
        else
        {
            System.out.println("Weird");
        }
        scanner.skip("(\r\n|[\n\r\u2028\u2029\u0085])?");

        scanner.close();
    }
}