- Rotate Image
You are given an n x n 2D matrix representing an image.
Rotate the image by 90 degrees (clockwise).
Note:
You have to rotate the image in-place, which means you have to modify the input 2D matrix directly. DO NOT allocate another 2D matrix and do the rotation.
Example 1:
Given input matrix =
[
[1,2,3],
[4,5,6],
[7,8,9]
],
rotate the input matrix in-place such that it becomes:
[
[7,4,1],
[8,5,2],
[9,6,3]
]
Example 2:
Given input matrix =
[
[ 5, 1, 9,11],
[ 2, 4, 8,10],
[13, 3, 6, 7],
[15,14,12,16]
],
rotate the input matrix in-place such that it becomes:
[
[15,13, 2, 5],
[14, 3, 4, 1],
[12, 6, 8, 9],
[16, 7,10,11]
]
my thoughts:
1. iterate the left-up quarter of the matrix; rotate. Tricky part is for even n, the quarter is just the quarter; for odd n, the quarter need to be a l = w+1 retangle to avoid rotating mid line twice.
my solution:
**********66 ms
class Solution:
def rotate(self, matrix):
"""
:type matrix: List[List[int]]
:rtype: void Do not return anything, modify matrix in-place instead.
"""
n = len(matrix)
for i in range((n+1)//2):
for j in range((n)//2):
cor_set = [[j, n-i-1], [n-i-1, n-j-1], [n-j-1, i], [i, j]]
pval = matrix[i][j]
#print(cor_set)
for k in range(4):
cor = cor_set[k]
temp = matrix[cor[0]][cor[1]]
matrix[cor[0]][cor[1]] = pval
pval = temp
my comments:
from other ppl's solution:
1. use extra space speed up the solution a little, 52ms:
class Solution:
def rotate(self, matrix):
"""
:type matrix: List[List[int]]
:rtype: void Do not return anything, modify matrix in-place instead.
"""
row = len(matrix)
col = len(matrix[0])
result =[]
for c in range(col):
r = row-1
for i in range(row):
result.append(matrix[r][c])
r -= 1
matrix.append(result)
result = []
for each in range(row):
matrix.remove(matrix[0])
2. need to look into zip(), 49ms:
class Solution:
def rotate(self, matrix):
"""
:type matrix: List[List[int]]
:rtype: void Do not return anything, modify matrix in-place instead.
"""
matrix[:] = zip(*matrix[::-1])