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threshold = 0.01
diff = abs((actualJsonValue - baseJsonValue)/baseJsonValue)
if diff > threshold; then regard as diff;
else, it regard as no diff
In this case
abs((101-100) / 100) > 0.01 is false, so key a is no diff
abs((105-100) / 100) > 0.01 is ture, so key b is diff
The text was updated successfully, but these errors were encountered:
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The text was updated successfully, but these errors were encountered: