Extract the inferred type is not working as expected

[wesleyfeitosa]

In documentation says that we can infer the type from a schema like this:

But when I try this with the example above, I was expecting attributes required by default and optional only for those I set as optional...

import { z } from 'zod';

export const createDiscountCouponSchema = z.object({
  accountId: z.number().optional(),
  coupon: z.string(),
  additionalDiscount: z.number(),
  expirationDate: z.date(),
  status: z.string(),
  campaign: z.string().optional(),
});

export type CreateDiscountCouponDto = z.infer<
  typeof createDiscountCouponSchema
>;

however, I'm receiving all attributes as optionals,

is that right?

I'm using zod 3.22.2 and typescript 5.0.3

[antonmoiseev]

I have the same issue. zod - 3.22.2 (tried with 3.21.4 as well), typescript - 5.1.6

[dudubernardino]

it works for me when i changed strict to true, take a look in docs about that requirements

// tsconfig.json
{
  // ...
  "compilerOptions": {
    // ...
    "strictNullChecks": true
  }
}

[wesleyfeitosa]

it works for me when i changed strict to true, take a look in docs about that requirements

// tsconfig.json
{
  // ...
  "compilerOptions": {
    // ...
    "strictNullChecks": true
  }
}

Thanks @dudubernardino, it worked for me