Not able to plot values in linechart

[anickt]

I have added my issue on stack overflow please check the link

[liuxuan30]

Would you please debug on your side? As the line starts turning around, there is no obvious reason to not draw the last 6 value pairs, you can first add some breakpoints at drawDataSets in line chart renderer, to see if all your missing values are there, and if the loop condition mets.

[anickt]

In data set I am getting all values see below:

ChartDataEntry, x: 0.0, y 0.62020133693747
ChartDataEntry, x: 0.0, y 0.62020133693747
ChartDataEntry, x: 0.0, y 0.62020133693747
ChartDataEntry, x: 8500.0, y 0.62020133693747
ChartDataEntry, x: 8500.0, y 0.925703706122449
ChartDataEntry, x: 9000.0, y 0.925703706122449
ChartDataEntry, x: 9000.0, y 1.43307403327373
ChartDataEntry, x: 9500.0, y 1.43307403327373
ChartDataEntry, x: 9500.0, y 0.37799568
ChartDataEntry, x: 9500.0, y 0.37799568
ChartDataEntry, x: 9500.0, y 0.37799568
ChartDataEntry, x: 9000.0, y 0.37799568
ChartDataEntry, x: 9000.0, y 0.269996914285714
ChartDataEntry, x: 8500.0, y 0.269996914285714
ChartDataEntry, x: 8500.0, y 0.239997257142857
ChartDataEntry, x: 6000.0, y 0.239997257142857
ChartDataEntry, x: 6000.0, y 0.219552079597251
ChartDataEntry, x: 0.0, y 0.219552079597251
ChartDataEntry, x: 0.0, y 0.453594816
ChartDataEntry, x: 0.0, y 0.453594816

[anickt]

Can you try to plot this value in line-chart from your end?

[liuxuan30]

I don't have time to put them in the demo yet. You can try first. Have you checked what I said?

[thierryH91200]

the problem is here

in BarLineScatterCandleBubbleRenderer

open class XBounds
  {
      /// minimum visible entry index
      open var min: Int = 0

      /// maximum visible entry index
      open var max: Int = 0

      /// range of visible entry indices
      open var range: Int = 0

      public init()
      {
          
      }
      
      public init(chart: BarLineScatterCandleBubbleChartDataProvider,
                  dataSet: IBarLineScatterCandleBubbleChartDataSet,
                  animator: Animator?)
      {
          self.set(chart: chart, dataSet: dataSet, animator: animator)
      }
      
      /// Calculates the minimum and maximum x values as well as the range between them.
      open func set(chart: BarLineScatterCandleBubbleChartDataProvider,
                    dataSet: IBarLineScatterCandleBubbleChartDataSet,
                    animator: Animator?)
      {
          let phaseX = Swift.max(0.0, Swift.min(1.0, animator?.phaseX ?? 1.0))
          
          let low = chart.lowestVisibleX
          let high = chart.highestVisibleX
          
          let entryFrom = dataSet.entryForXValue(low, closestToY: Double.nan, rounding: ChartDataSetRounding.down)
          let entryTo = dataSet.entryForXValue(high, closestToY: Double.nan, rounding: ChartDataSetRounding.up)
          
          self.min = entryFrom == nil ? 0 : dataSet.entryIndex(entry: entryFrom!)
          self.max = entryTo == nil ? 0 : dataSet.entryIndex(entry: entryTo!)
//          self.max = 20
          range = Int(Double(self.max - self.min) * phaseX)
      }
  }

add the last line

self.max = 20

[anickt]

Hey @liuxuan30 I tried what you said. I am getting all 20 values in data-set.
and @thierryH91200 when I added that line it was crashing the app.

[thierryH91200]

change the value to 18

[anickt]

Yes It Works. But this is not an ideal solution. How can I set this value from outside of the library?

[thierryH91200]

let tab = [[0.0, 0.62020133693747],
           [0.0, 0.62020133693747],
           [0.0, 0.62020133693747],
           [8500.0, 0.62020133693747],
           [8500.0,  0.925703706122449],
           [ 9000.0,  0.925703706122449],
           [ 9000.0,  1.43307403327373],
           [ 9500.0,  1.43307403327373],
           [ 9500.0,  0.37799568],
           [ 9500.0,  0.37799568],
           [ 9500.0,  0.37799568],
           [ 9000.0,  0.37799568],
           [ 9000.0,  0.269996914285714],
           [ 8500.0,  0.269996914285714],
           [ 8500.0,  0.239997257142857],
           [ 6000.0,  0.239997257142857],
           [ 6000.0,  0.219552079597251],
           [ 0.0,  0.219552079597251],
           [ 0.0,  0.453594816],
           [  0.0,  0.453594816]]


for i in 0..<tab.count {
    let x = tab[i][0]
    let y = tab[i][1]
    yVals1.append(ChartDataEntry(x: x, y: y))
}

print( tab.count)

set1 = LineChartDataSet(values: yVals1, label: "DataSet 1")
set1.axisDependency = .left

var dataSets = [LineChartDataSet]()
dataSets.append(set1)
let data = LineChartData(dataSets: dataSets)
chartView.data = data

for me it is good

remove UIImage ....

Try the simplest

[liuxuan30]

@thierryH91200 are you suggesting entryTo has bug?
I don't know why set self.max = 18

[anickt]

Yes even I don't understand

[thierryH91200]

it's not really a bug

 /// Calculates the minimum and maximum x values as well as the range between them.
      open func set(chart: BarLineScatterCandleBubbleChartDataProvider,
                    dataSet: IBarLineScatterCandleBubbleChartDataSet,
                    animator: Animator?)
      {

Charts does not like too much backwards in time on the OX axis
The simplest is to create 2 increasing datasets that meet

max = 18 or 20 this is the same thing = tab.count => values duplicates

let tab1 = [[0.0, 0.62020133693747],
           [0.0, 0.62020133693747],
           [0.0, 0.62020133693747],
           [8500.0, 0.62020133693747],
           [8500.0,  0.925703706122449],
           [ 9000.0,  0.925703706122449],
           [ 9000.0,  1.43307403327373],
           [ 9500.0,  1.43307403327373],
           [ 9500.0,  0.37799568],
           [ 9500.0,  0.37799568],
           [ 9500.0,  0.37799568]]

let tab2=
           [[  0.0,  0.453594816]]
           [ 0.0,  0.453594816],
           [ 0.0,  0.219552079597251],
           [ 6000.0,  0.219552079597251],
           [ 6000.0,  0.239997257142857],
           [ 8500.0,  0.239997257142857],
           [ 8500.0,  0.269996914285714],
           [ 9000.0,  0.269996914285714],
           [ 9000.0,  0.37799568]]

or modify
open func set
this is dangerous

[liuxuan30]

ok, thanks. Seems we can close this