Easy way to define a inline class which inherits all members of the base class.

[Cat-sushi]

typedef is a easy way to define a alias of a type, but it doesn't have separate static type to be completed, inferred or checked.
On the other hand, inline class doesn't inherit members of base class.
I want to have easy way to define a inline class which inherits all members of the base class.

For example,

inline class Db = Map<int, String>;

[rubenferreira97]

I really wish something like this was possible. Sometimes I only want to define a superset of operations to a static type. Forwarding the whole constructor is verbose (and in this case I don't really want to create a new class with overhead, just inline it).

Example with an extension:

// Some syntax to combine "inline + extension" would be perfect but I understand if this is too much to ask
inline class MyCustomMap<K,V> = Map<K,V>;

extension on MyCustomMap<K,V> {
   void fancyMethod() => print('Fancy');
}

final Map<int,int> map = {1:1};
map.fancyMethod(); //compile error
final MyCustomMap<int,int> fancyMap = {1,1};
fancyMap.fancyMethod(); //fine

[Cat-sushi]

A modifier might be better to override(?) some members of the base class.

inline class LruCache<K, V> {
  inherits Map<K, V> map;
  static int size = 100;

  @override // ?
  V? operator [](K key) {
    var value = map.remove(key);
    if(value != null) {
      map[key] = value;
    }
    return value;
  }

  @override // ?
  void operator []=(K key, V value) {
    map.remove(key);
    map[key] = value;
    if(map.length > size) {
      map.remove(map.keys.first);
    }
  }
}

[eernstg]

Cf. #2506.

[Cat-sushi]

@eernstg Thank you for your information.
#2506 satisfies my wants.
Closing this issue as duplicated.