Small problem on updated ahead when using print_ln

[winnnnnny]

Sorry for disturbing you.
I observed a small problem that the value of the variable would be updated ahead of the update function when the value is printed.
Here is an example.

a = sint(5)
b = sint(10)
# An update in the following line is necessary for triggering strange behavior
a.update(sint(6))
var1 = sint(0)
var2 = sint(97)
# An update in the following line is necessary for triggering strange behavior
var2.update(sint(17))
# var1 should still be 0, but the value is updated in advance from the "var1.update(b)".
print_ln('var1: %s', var1.reveal())
# An update using var1 in the following line is necessary for triggering strange behavior. 
var2.update(var1 + var1)
# var2 shows the correct value
print_ln('var2: %s', var2.reveal())
# som meaningless code
var3 = sint(0)
var4 = sint(1)
# var1 should be updated there
var1.update(b)
# var1 should be printed out to trigger the strange behavior
print_ln('var1: %s', var1.reveal())

The result is shown below.

./Scripts/mascot.sh test
Running /home/mp-spdz/Scripts/../mascot-party.x 0 test -pn 10468 -h localhost -N 2
Running /home/mp-spdz/Scripts/../mascot-party.x 1 test -pn 10468 -h localhost -N 2
Using security parameter 40
var1: 10
var2: 0
var1: 10
The following benchmarks are including preprocessing (offline phase).
Time = 0.00163745 seconds 
Data sent = 0.041528 MB in ~45 rounds (party 0 only; use '-v' for more details)
Global data sent = 0.083056 MB (all parties)

The problem only affects the printed value. The other calculation can be conducted successfully. May you make the print function works more correctly?

[mkskeller]

Thank you for raising this. You should find that 7f88a8b fixes it.

[winnnnnny]

Thank you for repairing this!