How to get startup path from assembly in Single Exe File

[OmidID]

I don't know is it a bug or not.
After I published my application using this command dotnet publish -r win-x64 -c Release /p:PublishSingleFile=true I'm not able to get the correct startup address from the code below:

var executablePath = Path.GetFullPath(typeof(Program).Assembly.Location);

The output is in the temp directory and it's dll file. Something like this:
C:\Users\MyUser\AppData\Local\Temp\.net\MyApp\po5w3wnz.iiu\MyApp.dll

[khellang]

I guess this is because it's basically embedding the DLL in a generated assembly and extracting it to a temp location before loading the DLL. Seems like it's a known issue; https://github.com/dotnet/coreclr/issues/20287#issuecomment-504287272

[Symbai]

It's not an issue rather a breaking change if you come from .NET Framework and dot net team suggests to use GetModuleFileNameW API is Process.GetCurrent().Mainmodule.Filename.

[OmidID]

Yea, this is what I already did in my code. I created this issue because I wasn't sure the assembly location should be the execution file or extracted one.

[khellang]

I wasn't sure the assembly location should be the execution file or extracted one.

Well, you did ask for the location of the assembly containing Program, which is the extracted assembly. If you want the executing assembly, you might want to use on of the static Assembly methods.