mult_of_3_5.py

# If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.

# Find the sum of all the multiples of 3 or 5 below 1000.

s = 0
for i in range(1,1000):
    if(i%3==0 or i%5==0):
        s+=i

print(s)

# 233168