forked from someshgkale123/LeetCode-Easy
-
Notifications
You must be signed in to change notification settings - Fork 2
/
Find the Town Judge
45 lines (35 loc) · 1.18 KB
/
Find the Town Judge
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
Problem Statement:
In a town, there are N people labelled from 1 to N. There is a rumor that one of these people is secretly the town judge.
If the town judge exists, then:
The town judge trusts nobody.
Everybody (except for the town judge) trusts the town judge.
There is exactly one person that satisfies properties 1 and 2.
You are given trust, an array of pairs trust[i] = [a, b] representing that the person labelled a trusts the person labelled b.
If the town judge exists and can be identified, return the label of the town judge. Otherwise, return -1.
Example 1:
Input: N = 2, trust = [[1,2]]
Output: 2
Example 2:
Input: N = 3, trust = [[1,3],[2,3]]
Output: 3
Example 3:
Input: N = 3, trust = [[1,3],[2,3],[3,1]]
Output: -1
Example 4:
Input: N = 3, trust = [[1,2],[2,3]]
Output: -1
Example 5:
Input: N = 4, trust = [[1,3],[1,4],[2,3],[2,4],[4,3]]
Output: 3
Solution:
class Solution:
def findJudge(self, N: int, trust: List[List[int]]) -> int:
dict={}
li=[0]*(N+1)
for i,j in trust:
dict[i]=j
li[j]+=1
for i in range(1,len(li)):
if li[i]>=(N-1) and i not in dict:
return i
return -1