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Message: On some systems (though not Linux-based systems) an attempt to free() results from memalign() may fail. This may, on a few systems, be exploitable. Also note that memalign() may not check that the boundary parameter is correct (CWE-676). Use posix_memalign instead (defined in POSIX's 1003.1d). Don't switch to valloc(); it is marked as obsolete in BSD 4.3, as legacy in SUSv2, and is no longer defined in SUSv3. In some cases, malloc()'s alignment may be sufficient.
johnsonjh
changed the title
On some systems (though not Linux-based systems) an attempt to free() results from memalign() may fail. This may, on a few systems, be exploitable. Also note that memalign() may not check that the boundary parameter is correct (CWE-676). Use posix_memalign instead (defined in POSIX's 1003.1d). Don't switch to valloc(); it is marked as obsolete in BSD 4.3, as legacy in SUSv2, and is no longer defined in SUSv3. In some cases, malloc()'s alignment may be sufficient.
memalign() may fail #1
Jun 10, 2021
Codacy detected an issue:
Message:
On some systems (though not Linux-based systems) an attempt to free() results from memalign() may fail. This may, on a few systems, be exploitable. Also note that memalign() may not check that the boundary parameter is correct (CWE-676). Use posix_memalign instead (defined in POSIX's 1003.1d). Don't switch to valloc(); it is marked as obsolete in BSD 4.3, as legacy in SUSv2, and is no longer defined in SUSv3. In some cases, malloc()'s alignment may be sufficient.
Occurred on:
#define memalign(ALIGNMENT, SIZE) \
Currently on:
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