HW_1_2_Counter_max.ipynb

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   "source": [
    "## Домашнее задание №1.2\n",
    "Найти в строке из 0 и 1 максимальную последовательность из единиц"
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   "cell_type": "markdown",
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    "#### Генерация случайной строки"
   ]
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     "text": [
      "0101111001101010010001011000001110100011111011101011010010010001010111011110001110011001101111011001\n"
     ]
    }
   ],
   "source": [
    "import random\n",
    "\n",
    "\n",
    "# случайная строка из \"0\" и \"1\"\n",
    "random_string = ''.join(random.choice(\"01\") for i in range(10**6))\n",
    "print(random_string[:100])"
   ]
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   "cell_type": "markdown",
   "id": "bf1593cd-b265-4b2b-b811-fe12f6dc18e8",
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   "source": [
    "#### Алгоритмы поиска"
   ]
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     "text": [
      "Wall time: 0 ns\n",
      "22\n"
     ]
    }
   ],
   "source": [
    "# поиск максимальной последовательности из 1 через разбивку строки в список\n",
    "%time\n",
    "#lst = random_string.split(\"0\")\n",
    "print(max(len(x) for x in random_string.split(\"0\")))"
   ]
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      "Wall time: 0 ns\n",
      "22\n"
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   "source": [
    "#поиск по счётчикам через цикл\n",
    "%time\n",
    "counter = 0\n",
    "temp_count = 0\n",
    "for i in random_string:\n",
    "    if i == \"1\":\n",
    "        temp_count += 1\n",
    "    else:\n",
    "        if temp_count > counter:\n",
    "            counter = temp_count\n",
    "        temp_count = 0\n",
    "if temp_count > counter:\n",
    "    counter = temp_count\n",
    "print(counter)"
   ]
  }
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