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If the filter sizes get too large (~100x100 or larger), it makes more sense to use the convolutional theorem:
ifft(fft(A).*fft(B))
The text was updated successfully, but these errors were encountered:
leios
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Filter should be done via convolutional theorem at larger scales
Filters should be done via convolutional theorem at larger scales
Jan 11, 2023
If the filter sizes get too large (~100x100 or larger), it makes more sense to use the convolutional theorem:
ifft(fft(A).*fft(B))
The text was updated successfully, but these errors were encountered: