Given the head
of a singly linked list and two integers left
and right
where left <= right
, reverse the nodes of the list from position left
to position right
, and return the reversed list.
Example 1:
Input: head = [1,2,3,4,5], left = 2, right = 4 Output: [1,4,3,2,5]
Example 2:
Input: head = [5], left = 1, right = 1 Output: [5]
Constraints:
- The number of nodes in the list is
n
. 1 <= n <= 500
-500 <= Node.val <= 500
1 <= left <= right <= n
Follow up: Could you do it in one pass?
Companies:
Microsoft, Amazon, Facebook, Bloomberg
Related Topics:
Linked List
Similar Questions:
// OJ: https://leetcode.com/problems/reverse-linked-list-ii/
// Author: github.com/lzl124631x
// Time: O(N)
// Space: O(1)
class Solution {
public:
ListNode* reverseBetween(ListNode* head, int m, int n) {
ListNode dummy, *p = &dummy;
dummy.next = head;
for (int i = 1; i < m; ++i) p = p->next;
auto q = p->next, tail = q;
for (int i = m; i <= n; ++i) {
auto node = q;
q = q->next;
node->next = p->next;
p->next = node;
}
tail->next = q;
return dummy.next;
}
};