Type alias is not possible when defining abstract method.

[fphh]

This gives an compile error:

type t = () => void;

abstract class A {
   abstract f : t
}

This compiles:

abstract class A {
  abstract f () : void; 
}

Shouldn't both be possible if we support type aliases?

I used Typescript 1.7.5.

[mhegazy]

looks like a duplicate of #4669

[fphh]

I don't see that #4669 has to do with type aliases. Actually, I think that, if my first example does not compile, this means type aliasing is not fully implemented or broken.

[kbtz]

Please reopen this one.

[mhegazy]

abstract properties are not legal in TS today. #4669 tracks enabling it. This has nothing to do with type aliases.. abstract class C { abstract c: number; } still does not compiler.

[fphh]

If we had abstract properties, then my first example would compile? Note, that by type f is still a method, not an property (even if it looks syntactically like a property).

[mhegazy]

If we had abstract properties, then my first example would compile?

yes. this is #4669