Unable to make a function conform to an overloaded callable protocol

[Azureblade3808]

Environment data

• Language Server version: 2021.5.1
• OS and version: Windows 7
• Python version (& distribution if applicable, e.g. Anaconda): 3.8.8 Anaconda

Sample

from __future__ import annotations

from typing import Any, Protocol, overload

class P(Protocol):
    @overload
    def __call__(self, x: int, /) -> int:
        ...

    @overload
    def __call__(self, x: str, /) -> str:
        ...

    def __call__(self, x: Any, /) -> Any:
        ...

def f0(x: Any, /) -> Any:
    return x

a: P = f0

@overload
def f1(x: int, /) -> int:
    ...

@overload
def f1(x: str, /) -> str:
    ...

def f1(x: Any, /) -> Any:
    return x

b: P = f1

Expected behavior

No errors/warnings.

Actual behaviour

Both assignments got warnings.

[erictraut]

Thanks for the bug report. This will be fixed in the next release.

[jakebailey]

This issue has been fixed in version 2021.5.3, which we've just released. You can find the changelog here: https://github.com/microsoft/pylance-release/blob/main/CHANGELOG.md#202153-19-may-2021