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Prbl189RotateArray.java
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package leetcode.editor.en;
import java.util.logging.Logger;
//2021-08-27 17:18:59
//java: Rotate Array
//QuestionId: 189
public class Prbl189RotateArray {
private static final Logger logger = Logger.getLogger(Logger.GLOBAL_LOGGER_NAME);
public static void main(String[] args) {
Solution solution = new Prbl189RotateArray().new Solution();
}
//leetcode submit region begin(Prohibit modification and deletion)
class Solution {
public void rotate(int[] nums, int k) {
if (nums == null || nums.length < 2) {
return;
}
k = k % nums.length;
// [1,2,3,4,5,6,7] => [4,3,2,1,5,6,7]
reverseHelper(nums, 0, nums.length - k - 1);
// [4,3,2,1,5,6,7] => [4,3,2,1,7,6,5]
reverseHelper(nums, nums.length - k, nums.length - 1);
// [4,3,2,1,7,6,5] => [5,6,7,1,2,3,4]
reverseHelper(nums, 0, nums.length - 1);
}
private void reverseHelper(int[] nums, int i, int j) {
while (i < j) {
nums[i] ^= nums[j];
nums[j] ^= nums[i];
nums[i++] ^= nums[j--];
}
}
}
//leetcode submit region end(Prohibit modification and deletion)
}
//Given an array, rotate the array to the right by k steps, where k is non-
//negative.
//
//
// Example 1:
//
//
//Input: nums = [1,2,3,4,5,6,7], k = 3
//Output: [5,6,7,1,2,3,4]
//Explanation:
//rotate 1 steps to the right: [7,1,2,3,4,5,6]
//rotate 2 steps to the right: [6,7,1,2,3,4,5]
//rotate 3 steps to the right: [5,6,7,1,2,3,4]
//
//
// Example 2:
//
//
//Input: nums = [-1,-100,3,99], k = 2
//Output: [3,99,-1,-100]
//Explanation:
//rotate 1 steps to the right: [99,-1,-100,3]
//rotate 2 steps to the right: [3,99,-1,-100]
//
//
//
// Constraints:
//
//
// 1 <= nums.length <= 10⁵
// -2³¹ <= nums[i] <= 2³¹ - 1
// 0 <= k <= 10⁵
//
//
//
// Follow up:
//
//
// Try to come up with as many solutions as you can. There are at least three
//different ways to solve this problem.
// Could you do it in-place with O(1) extra space?
//
// Related Topics Array Math Two Pointers 👍 5446 👎 980