-
Notifications
You must be signed in to change notification settings - Fork 29
/
0006-ZigZag-Conversion.py
43 lines (35 loc) · 1.07 KB
/
0006-ZigZag-Conversion.py
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
'''
The string "PAYPALISHIRING" is written in a zigzag pattern on a given number of rows like this: (you may want to display this pattern in a fixed font for better legibility)
P A H N
A P L S I I G
Y I R
And then read line by line: "PAHNAPLSIIGYIR"
Write the code that will take a string and make this conversion given a number of rows:
string convert(string s, int numRows);
Example 1:
Input: s = "PAYPALISHIRING", numRows = 3
Output: "PAHNAPLSIIGYIR"
Example 2:
Input: s = "PAYPALISHIRING", numRows = 4
Output: "PINALSIGYAHRPI"
Explanation:
P I N
A L S I G
Y A H R
P I
'''
class Solution:
def convert(self, s: str, numRows: int) -> str:
if numRows == 1:
return s
res = ''
n = len(s)
cycle_len = 2 * numRows - 2
for i in range(numRows):
j = 0
while j + i < n:
res += s[j + i]
if i != 0 and i != numRows - 1 and j + cycle_len - i < n:
res += s[j + cycle_len - i]
j += cycle_len
return res