map string string fails to compile #176
Labels
confirmed
kind: bug
solution: wontfix
the issue will not be fixed (either it is impossible or deemed out of scope)
Comments
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Just to make sure: in your comment, you mean // if I change to map<std::string,std::string> then it compilesand not // if I change to map<string,int> then it compiles |
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no, I mean that if I change to: then it compiles as it should |
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I have not analyzed the bug deeper, but the issue seems not to be type alias. The following code also fails to compile: #include <json.hpp>
using nlohmann::json;
int main()
{
std::map<std::string, std::string> t;
// this works
json s = t;
// the fails
s.get<std::map<std::string, std::string>>();
} |
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Same error with a more concise example: #include <json.hpp>
using nlohmann::json;
int main()
{
json s = json::object();
std::map<std::string, std::string> m = s;
}Error: |
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This function triggered the error: /// get an object (explicit)
template <class T, typename
std::enable_if<
std::is_convertible<typename object_t::key_type, typename T::key_type>::value and
std::is_convertible<basic_json_t, typename T::mapped_type>::value
, int>::type = 0>
T get_impl(T*) constThis function tries to return an object of type #include <json.hpp>
using nlohmann::json;
int main()
{
json::object_t s;
std::map<std::string, std::string>(s.begin(), s.end());
}For the last line's constructor, the documentation states for the iterators:
This can reduce the example to #include <json.hpp>
using nlohmann::json;
int main()
{
json::object_t::value_type s;
std::map<std::string, std::string>::value_type t(s);
} |
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Further reduction: #include <json.hpp>
using nlohmann::json;
int main()
{
json s;
std::string t(s);
}error: |
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Found this comment on StackOverflow, quoting cppreference:
Indeed, |
nlohmann
added
the
solution: wontfix
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I fail to compile this piece of code:
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