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circular-array-rotation.cpp
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circular-array-rotation.cpp
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// https://www.hackerrank.com/challenges/circular-array-rotation/problem
// WARNING: This solutions got 12/1000, please do a pull request if you have a better solution
#include <bits/stdc++.h>
using namespace std;
vector<string> split_string(string);
// Complete the circularArrayRotation function below.
vector<int> circularArrayRotation(vector<int> a, int k, vector<int> queries) {
// K is the number of cicles -
// For every rottion cycle, the last became the first element and all the other
// elements shift forwards
int len = a.size();
vector<int>solution;
int last;
for(int i=0; i < k; i++)
{
last = a[len-1];
for(int j = len-1; j >0; j--)
a[j] = a[j-1];
a[0] = last;
}
for(int i =0; i < queries.size(); i++)
{
solution.push_back(a[queries[i]]);
}
return solution;
}
int main()
{
ofstream fout(getenv("OUTPUT_PATH"));
string nkq_temp;
getline(cin, nkq_temp);
vector<string> nkq = split_string(nkq_temp);
int n = stoi(nkq[0]);
int k = stoi(nkq[1]);
int q = stoi(nkq[2]);
string a_temp_temp;
getline(cin, a_temp_temp);
vector<string> a_temp = split_string(a_temp_temp);
vector<int> a(n);
for (int i = 0; i < n; i++) {
int a_item = stoi(a_temp[i]);
a[i] = a_item;
}
vector<int> queries(q);
for (int i = 0; i < q; i++) {
int queries_item;
cin >> queries_item;
cin.ignore(numeric_limits<streamsize>::max(), '\n');
queries[i] = queries_item;
}
vector<int> result = circularArrayRotation(a, k, queries);
for (int i = 0; i < result.size(); i++) {
fout << result[i];
if (i != result.size() - 1) {
fout << "\n";
}
}
fout << "\n";
fout.close();
return 0;
}
vector<string> split_string(string input_string) {
string::iterator new_end = unique(input_string.begin(), input_string.end(), [] (const char &x, const char &y) {
return x == y and x == ' ';
});
input_string.erase(new_end, input_string.end());
while (input_string[input_string.length() - 1] == ' ') {
input_string.pop_back();
}
vector<string> splits;
char delimiter = ' ';
size_t i = 0;
size_t pos = input_string.find(delimiter);
while (pos != string::npos) {
splits.push_back(input_string.substr(i, pos - i));
i = pos + 1;
pos = input_string.find(delimiter, i);
}
splits.push_back(input_string.substr(i, min(pos, input_string.length()) - i + 1));
return splits;
}