Treat digits as a continuous word

[GregHib]

If [WordSplitterConfig.handleCase] is set to true: if a lowercase character is followed by an uppercase character, a word boundary is considered to be prior to the uppercase character.
If [WordSplitterConfig.handleCase] is set to true: if multiple uppercase characters are followed by a lowercase character, a word boundary is considered to be prior to the last uppercase character.

Prior to the last digit is an odd place to be considered a boundary. As such any digits which are followed by letters get chopped up.

Input	Expected	Actual
option14b	option 14 b	option 1 4b
123abc	123 abc	12 3abc

Numbers should be considered continuous

[mrapplexz]

Hello! Sorry, for a late reply, but I'm currently busy at work. I will look into this issue when I'll have some time :)