-
Notifications
You must be signed in to change notification settings - Fork 77
/
Copy path257.二叉树的所有路径.go
74 lines (70 loc) · 1.35 KB
/
257.二叉树的所有路径.go
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
/*
* @lc app=leetcode.cn id=257 lang=golang
*
* [257] 二叉树的所有路径
*
* https://leetcode-cn.com/problems/binary-tree-paths/description/
*
* algorithms
* Easy (66.43%)
* Likes: 436
* Dislikes: 0
* Total Accepted: 93.5K
* Total Submissions: 140.7K
* Testcase Example: '[1,2,3,null,5]'
*
* 给定一个二叉树,返回所有从根节点到叶子节点的路径。
*
* 说明: 叶子节点是指没有子节点的节点。
*
* 示例:
*
* 输入:
*
* 1
* / \
* 2 3
* \
* 5
*
* 输出: ["1->2->5", "1->3"]
*
* 解释: 所有根节点到叶子节点的路径为: 1->2->5, 1->3
*
*/
// @lc code=start
/**
* Definition for a binary tree node.
* type TreeNode struct {
* Val int
* Left *TreeNode
* Right *TreeNode
* }
*/
func binaryTreePaths(root *TreeNode) []string {
ret := make([]string, 0)
helper(root, "", &ret)
return ret
}
func helper(root *TreeNode, path string, ret *[]string) {
if root == nil {
return
}
var newPath string
if path == "" {
newPath = fmt.Sprintf("%d", root.Val)
} else {
newPath = fmt.Sprintf("%s->%d", path, root.Val)
}
if root.Left == nil && root.Right == nil {
*ret = append(*ret, newPath)
return
}
if root.Left != nil {
helper(root.Left, newPath, ret)
}
if root.Right != nil {
helper(root.Right, newPath, ret)
}
}
// @lc code=end