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MST1.cpp
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MST1.cpp
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#include <bits/stdc++.h>
using namespace std;
#define mod 1000000007
#define inf 1e9
typedef long long ll;
typedef long double ld;
typedef unsigned long long int ul;
typedef vector<int> vi;
typedef vector<ll> vl;
typedef vector<bool> vb;
typedef vector<float> vf;
typedef vector <ld> vd;
typedef pair<int,int> pii;
typedef pair<ll,ll> pll;
typedef pair<ld,ld> pdd;
typedef vector<pii> vii;
typedef vector<pll> vll;
#define vec(x) vector<x >
#define z size()
#define get1(x) cin>>x
#define get2(x, y) cin>>x>>y
#define get3(x, y, z) cin>>x>>y>>z
#define put(x) cout<<x
#define pls(x) cout<<x<<' '
#define pln(x) cout<<x<<"\n"
#define f(i,a,b) for(int i=a;i<b;i++)
#define F(i,a,b) for(int i=b-1;i>=a;i--)
#define vput(a) f(i,0,a.z) pls(a[i]); nl;
#define vget(v) f(i,0,v.z) get1(v[i]);
#define vsort(v) sort(v.begin(),v.end())
#define all(v) v.begin(),v.end()
#define vuni(v) v.erase(unique(all(v)),v.end())
#define pb push_back
#define mp make_pair
#define X first
#define Y second
#define vmin(v) *min_element(all(v))
#define vmax(v) *max_element(all(v))
#define total(v) accumulate(all(v),ll(0))
#define watch(x) cout << (#x) << " is " << (x) << endl
#define bs(v,x) binary_search(all(v),x)
#define lb(v,x) lower_bound(all(v),x)-v.begin()
#define ub(v,x) upper_bound(all(v),x)-v.begin()
#define parray(a,n) f(i,0,n) pls(a[i]); nl;
#define ppair(x) cout<<x.first<<' '<<x.second<<"\n";
#define vp(x,y) vector<pair<x,y> >
#define p(x,y) pair<x,y >
#define endl '\n'
#define nl cout<<'\n';
#define w(a) while(a--)
#define wh(a) while(a)
ll maxi=LLONG_MAX;
ll mini=LLONG_MIN;
void fast() { ios_base::sync_with_stdio(false); cin.tie(NULL); }
void tick(){
static clock_t oldt;
clock_t newt=clock();
double diff=1.0*(newt-oldt)/CLOCKS_PER_SEC;
oldt = newt;
cout << '\n' << "The execution time is : " << diff << '\n';
}
int dp[20000005];
//Bottom Up
int minimumSteps(int n)
{
if(n<=1){
return dp[n] = 0;
}
if(dp[n]!=0)
return dp[n];
int ans1 = INT_MAX, ans2 = INT_MAX, ans3 = INT_MAX;
if(n%3==0)
ans3 = minimumSteps(n/3) + 1;
if(n%2==0)
ans2 = minimumSteps(n/2) + 1;
ans1 = minimumSteps(n-1) + 1;
return dp[n] = min(min(ans1, ans2), ans3);
}
int main(void)
{
fast();
#ifndef ONLINE_JUDGE
freopen("input.txt", "r", stdin);
freopen("output.txt", "w", stdout);
#endif
int t;
get1(t);
int j = 0;
memset(dp, 0, sizeof(dp));
w(t){
j++;
int n;
get1(n);
int ans = minimumSteps(n);
pls("Case");put(j);pls(":");pln(ans);
}
// tick();
}