Generated query to use rdf:type in match

[CyberDaedalus00]

When I generate a SPARQL query from a GraphQL query, I always see the statement in the WHERE clause is something like:

?df_3_0 <http://example.org/hero> ?hero.

which won't match anything in our knowledge base and thus cause the query to return with no results.

What I was expected was a statement more like:

?hero <http://www.w3.org/1999/02/22-rdf-syntax-ns#type> <http://example.org/hero>

which would then be followed by the remainder of the statements used to obtain the predicate values of interest.

Is there a way to get the code to generate that? Perhaps I've missed something.

[rubensworks]

Sure, you can use inline fragments for that: https://github.com/rubensworks/graphql-to-sparql.js#inline-fragments