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time_based_key_value_store.py
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# https://leetcode.com/problems/time-based-key-value-store/
# 981. Time Based Key-Value Store
# Look at binary_search.py
# Design a time-based key-value data structure that can store multiple values for the same key at different time stamps and retrieve the key's value at a certain timestamp.
# Implement the TimeMap class:
# TimeMap() Initializes the object of the data structure.
# void set(String key, String value, int timestamp) Stores the key key with the value value at the given time timestamp.
# String get(String key, int timestamp) Returns a value such that set was called previously, with timestamp_prev <= timestamp. If there are multiple such values, it returns the value associated with the largest timestamp_prev. If there are no values, it returns "".
# Example 1:
# Input
# ["TimeMap", "set", "get", "get", "set", "get", "get"]
# [[], ["foo", "bar", 1], ["foo", 1], ["foo", 3], ["foo", "bar2", 4], ["foo", 4], ["foo", 5]]
# Output
# [null, null, "bar", "bar", null, "bar2", "bar2"]
# Explanation
# TimeMap timeMap = new TimeMap();
# timeMap.set("foo", "bar", 1); // store the key "foo" and value "bar" along with timestamp = 1.
# timeMap.get("foo", 1); // return "bar"
# timeMap.get("foo", 3); // return "bar", since there is no value corresponding to foo at timestamp 3 and timestamp 2, then the only value is at timestamp 1 is "bar".
# timeMap.set("foo", "bar2", 4); // store the key "foo" and value "bar2" along with timestamp = 4.
# timeMap.get("foo", 4); // return "bar2"
# timeMap.get("foo", 5); // return "bar2"
# Constraints:
# 1 <= key.length, value.length <= 100
# key and value consist of lowercase English letters and digits.
# 1 <= timestamp <= 107
# All the timestamps timestamp of set are strictly increasing.
# At most 2 * 105 calls will be made to set and get.
from collections import defaultdict
from typing import List
class TimeMap:
''' Time Based Key-Value Store '''
def __init__(self):
self.store = defaultdict(list)
def set(self, key: str, value: str, timestamp: int) -> None:
self.store[key].append((timestamp, value))
def get(self, key: str, timestamp: int) -> str:
return self._search(key, timestamp)
def _search(self, key: str, target: int) -> int:
''' Binary Search approximately '''
bs_sourse = self.store[key]
output = ''
if bs_sourse is None:
return output
l, r = 0, len(bs_sourse) - 1
while l<=r:
mid = (l + r) // 2
if bs_sourse[mid][0] == target:
return bs_sourse[mid][1]
#left direction
elif bs_sourse[mid][0] > target:
r = mid - 1
#right direction
else:
l = mid + 1
# remember the last known value
output = bs_sourse[mid][1]
#ends when r < l
return output
# Your TimeMap object will be instantiated and called as such:
obj = TimeMap()
commands = ["get", "set", "get", "get", "set", "get", "get", "get", "get"]
resources = [["foo", 1], ["foo", "bar", 1], ["foo", 1], ["foo", 3], ["foo", "bar2", 4], ["foo", 4], ["foo", 5], ["foo", 2], ["too", 1]]
# Output
# ["", None, "bar", "bar", None, "bar2", "bar2", "bar", ""]
for com, inp in zip(commands, resources):
if com == 'set':
output = obj.set(inp[0],inp[1],inp[2])
print(output)
else:
param_2 = obj.get(inp[0],inp[1])
print(param_2)