Option to output colored file name only

[nkh]

Given "aaa/bbb/entry" return only "color + entry + color reset".

Use case:

I have "$HOME/downloads", which happens to be a link, and a lot of other files from different directories in a list and want to colorize them.

The only way to get correct colorization is to be in the right directory for each entry in the list, this means starting a process for each entry and is prohibitively expensive.

I can send the full path but then I'd have to parse the colored string.

An alternative would be to output the colored path and the colored entry on different lines.

[sharkdp]

Isn't this the same as #70?

[nkh]

@sharkdp

They are different.

issue 70

Add a user defined $root to every input entry

issue 78

output only the colored basename without the path

orthogonality

a list of files could be passed as arguments with --root $root to be added to the files and --name-only would only return the basename of the file colored according to the file present int $root (ie could exist and be executable in $root).

[tavianator]

You can do this with bfs:

$ bfs -color -prune -printf '%f\n' path/to/file1 path/to/file2
file1
file2

[nkh]

@tavianator I would but

positive: bfs is faster than lscolors
negative: bfs doesn't accepted files on stdin which is a show stopper for me

[tavianator]

If you can \0-separate them instead of \n, then it does support -files0-from -. If not, there's always xargs :)

[nkh]

@tavianator

I didn't get that far in the man page.

I'll probably end up writing a wrapper called 'lscolors' around 'bfs' till I find the time to replace it, I just found out that I use lscolors in 25 different places in my code!

[sharkdp]

See #80 for some changes related to this ticket.