Question about unpack()

[sktbrt]

Hi, I want to call soffice.bin directly.
However, it seems that unpack() does not exist above v4 (?)

aws-lambda-libreoffice/readme.md

Lines 86 to 98 in 47e61fc

	Or if you want more control:
	```js
	const {unpack, defaultArgs} = require('@shelf/aws-lambda-libreoffice');
	await unpack(); // default path /tmp/instdir/program/soffice.bin
	execSync(
	`/tmp/instdir/program/soffice.bin ${defaultArgs.join(
	' '
	)} --convert-to pdf file.docx --outdir /tmp`
	);
	```

Is there a way to do the same?

[sktbrt]

Solved

https://github.com/shelfio/aws-lambda-brotli-unpacker

example:

const { execSync } = require('child_process');
const { unpack } = require('@shelf/aws-lambda-brotli-unpacker');

module.exports.handler = async event => {
   const inputPath = '/opt/lo.tar.br';
   const outputPath = '/tmp/instdir/program/soffice.bin';
   const command = `${outputPath} ....... --convert-to pdf .......`;
   await unpack({inputPath, outputPath});
   execSync(command);
};

NOTE:
If you use unpack(), the subsequent convertTo() will fail.
So I decided to run everything with execSync.

/bin/sh: 1: libreoffice7.4: not found