1001. 害死人不偿命的(3n+1)猜想 (15)

#include<stdio.h>
  int main(){
    int cnt = 0;
    int x;
    scanf("%d",&x);
    if(x <= 1000){
      while(x != 1){
        if(x % 2 == 0){
          x /= 2;
        }else{
          x = (3*x + 1)/2;
        }
        cnt++;
      }
    }
    printf("%d",cnt);
    return 0;
  }