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question_14.cpp
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question_14.cpp
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/*
==> Smaller and Larger <==
Question Link:- https://practice.geeksforgeeks.org/problems/smaller-and-larger4005/1?page=1&difficulty[]=-2&category[]=Arrays&sortBy=submissions
Given a sorted array Arr of size N and a value X, find the number of
array elements less than or equal to X and elements more than or equal to X.
Example 1:
Input:
N = 7, X = 0
Arr[] = {1, 2, 8, 10, 11, 12, 19}
Output: 0 7
Explanation: There are no elements less or
equal to 0 and 7 elements greater or equal
to 0.
Example 2:
Input:
N = 7, X = 5
Arr[] = {1, 2, 8, 10, 11, 12, 19}
Output: 2 5
Explanation: There are 2 elements less or
equal to 5 and 5 elements greater or equal
to 5.
*/
#include <iostream>
#include <vector>
using namespace std;
void printVector( vector<int> v ) {
for ( int i = 0; i < v.size(); i++ ) cout << v[i] << " ";
}
vector<int> getMoreAndLess(int arr[], int n, int x) {
int less = 0, more = 0;
for ( int i = 0; i < n; i++ ) {
if ( arr[i] <= x ) less++;
if ( arr[i] >= x ) more++;
}
return { less, more };
}
int main () {
int arr [] = { 1, 2, 8, 10, 11, 12, 19 };
vector<int> ans = getMoreAndLess(arr, 7, 5);
printVector(ans);
return 0;
}