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Private Sub Login()
Dim s as String
s = "Login"
End Sub
The obfuscator changes both Logins:
Private Sub o10101010101()
Dim s as String
s = "o10101010101"
End Sub
It is because of this Pattern in your code: sPattern = "([\*\.\^\*\+\#\(\)\-\=\/\,\:\;\s\" & VBA.Chr$(34) & "])" & sFinde & "([\*\.\^\*\+\!\@\#\$\%\&\(\)\-\=\/\,\:\;\s\" & VBA.Chr$(34) & "]|$)"
Why exactly is there this VBA.Chr$(34)? Because of that Strings get obfuscated.
The text was updated successfully, but these errors were encountered:
With (?=([^"]*"[^"]*")*[^"]*$) you exclude EVERYTHING inside of quotes.
Of course, the Regex-Line also has to be changed to sCode = RegExpFindReplace(sCode, sPattern, "$1" & sReplace)
Example:
The obfuscator changes both Logins:
It is because of this Pattern in your code:
sPattern = "([\*\.\^\*\+\#\(\)\-\=\/\,\:\;\s\" & VBA.Chr$(34) & "])" & sFinde & "([\*\.\^\*\+\!\@\#\$\%\&\(\)\-\=\/\,\:\;\s\" & VBA.Chr$(34) & "]|$)"
Why exactly is there this
VBA.Chr$(34)
? Because of that Strings get obfuscated.The text was updated successfully, but these errors were encountered: