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一天一道LeetCode系列 ##(一)题目Given a string containing just the characters '(' and ')', find the length of the longest valid (well-formed) parentheses substring.
For "(()", the longest valid parentheses substring is "()", which has length = 2.
Another example is ")()())", where the longest valid parentheses substring is "()()", which has length = 4.
##(二)解题
/*
stack法思想:和Valid Parentheses一样,用stack来解决,只不过栈中记录的是每个‘(’的下标
1.首先在栈里面压入初始值-1(初始匹配失败的下标), 如果是‘(’就直接把‘(’的下标压进栈
2. 如果是‘)’开始判断
(1) 如果此刻栈的大小大于1,则将栈顶元素弹出,将下标减去当前的栈顶元素即为当前有效串的长度
(2) 如果此刻栈的大小小于等于1,则代表匹配失败,更新目前匹配失败的下标。
*/
class Solution {
public:
int longestValidParentheses(string s) {
stack<int> stmp;
stmp.push(-1);
int max = 0;
for(int i = 0 ; i < s.length() ; i++){
if(s[i] == '(')
{
stmp.push(i);
}
else
{
if(stmp.size()>1)
{
stmp.pop();
int len = i - stmp.top();
max = max>len?max:len;
}
else
{
stmp.pop();
stmp.push(i);
}
}
}
return max;
}
};