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189.rotate-array.1.go
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189.rotate-array.1.go
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/*
* @lc app=leetcode id=189 lang=golang
*
* [189] Rotate Array
*
* https://leetcode.com/problems/rotate-array/description/
*
* algorithms
* Easy (29.41%)
* Total Accepted: 285.3K
* Total Submissions: 962.8K
* Testcase Example: '[1,2,3,4,5,6,7]\n3'
*
* Given an array, rotate the array to the right by k steps, where k is
* non-negative.
*
* Example 1:
*
*
* Input: [1,2,3,4,5,6,7] and k = 3
* Output: [5,6,7,1,2,3,4]
* Explanation:
* rotate 1 steps to the right: [7,1,2,3,4,5,6]
* rotate 2 steps to the right: [6,7,1,2,3,4,5]
* rotate 3 steps to the right: [5,6,7,1,2,3,4]
*
*
* Example 2:
*
*
* Input: [-1,-100,3,99] and k = 2
* Output: [3,99,-1,-100]
* Explanation:
* rotate 1 steps to the right: [99,-1,-100,3]
* rotate 2 steps to the right: [3,99,-1,-100]
*
*
* Note:
*
*
* Try to come up as many solutions as you can, there are at least 3 different
* ways to solve this problem.
* Could you do it in-place with O(1) extra space?
*
*/
func reverse(s []int, start, end int) {
times := end - start
for i := times/2 - 1; i >= 0; i-- {
opp := end - 1 - i
s[i+start], s[opp] = s[opp], s[i+start]
}
}
func rotate(nums []int, k int) {
l := len(nums)
k = k % l
reverse(nums, 0, l-k)
reverse(nums, l-k, l)
reverse(nums, 0, l)
}