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for Gam function
h(x) function should only depend on x but in the solution it also depends on eta1.
Alternative solution,
taking x^eta1 as exp(eta1*ln(x)) we get
eta = same
h(x) = x^-1
g(eta) = same
u(x) = [ln(x) -1]
The text was updated successfully, but these errors were encountered:
for Gam function
h(x) function should only depend on x but in the solution it also depends on eta1.
Alternative solution,
taking x^eta1 as exp(eta1*ln(x)) we get
eta = same
h(x) = x^-1
g(eta) = same
u(x) = [ln(x) -1]
The text was updated successfully, but these errors were encountered: