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I was wondering, why does the implementation of manifold.stream/zip create an intermediary stream for each input stream instead of "zipping" the input streams directly?
The text was updated successfully, but these errors were encountered:
Because if loop/recur and connect based consumers are both given the same
stream, the loop/recur consumer may miss messages. Consider the case where
there are no intermediate streams, and we both map and zip over a
particular stream.
On Fri, Jul 22, 2016 at 3:19 PM Vadim Platonov notifications@github.com
wrote:
I was wondering, why does the implementation of
manifold.stream/zip
create an intermediary stream for each input stream instead of "zipping" the input streams directly?The text was updated successfully, but these errors were encountered: