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Merge pull request #1046 from 0xff-dev/2290
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Add solution and test-cases for problem 2290
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6boris authored Dec 24, 2024
2 parents 14aa847 + 70f66e2 commit a2736f7
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Original file line number Diff line number Diff line change
@@ -1,28 +1,36 @@
# [2290.Minimum Obstacle Removal to Reach Corner][title]

> [!WARNING|style:flat]
> This question is temporarily unanswered if you have good ideas. Welcome to [Create Pull Request PR](https://github.com/kylesliu/awesome-golang-algorithm)
## Description
You are given a **0-indexed** 2D integer array `grid` of size `m x n`. Each cell has one of two values:

- `0` represents an **empty** cell,
- `1` represents an **obstacle** that may be removed.

You can move up, down, left, or right from and to an empty cell.

Return the **minimum** number of **obstacles** to **remove** so you can move from the upper left corner `(0, 0)` to the lower right corner `(m - 1, n - 1)`.

**Example 1:**
**Example 1:**

![1](./1.png)

```
Input: a = "11", b = "1"
Output: "100"
Input: grid = [[0,1,1],[1,1,0],[1,1,0]]
Output: 2
Explanation: We can remove the obstacles at (0, 1) and (0, 2) to create a path from (0, 0) to (2, 2).
It can be shown that we need to remove at least 2 obstacles, so we return 2.
Note that there may be other ways to remove 2 obstacles to create a path.
```

## 题意
> ...
**Example 2:**

## 题解
![2](./2.png)

### 思路1
> ...
Minimum Obstacle Removal to Reach Corner
```go
```

Input: grid = [[0,1,0,0,0],[0,1,0,1,0],[0,0,0,1,0]]
Output: 0
Explanation: We can move from (0, 0) to (2, 4) without removing any obstacles, so we return 0.
```

## 结语

Expand Down
Original file line number Diff line number Diff line change
@@ -1,5 +1,61 @@
package Solution

func Solution(x bool) bool {
import "container/heap"

type heap2290 [][3]int

func (h *heap2290) Len() int {
return len(*h)
}

func (h *heap2290) Swap(i, j int) {
(*h)[i], (*h)[j] = (*h)[j], (*h)[i]
}

func (h *heap2290) Less(i, j int) bool {
return (*h)[i][2] < (*h)[j][2]
}

func (h *heap2290) Push(x any) {
*h = append(*h, x.([3]int))
}

func (h *heap2290) Pop() any {
old := *h
l := len(old)
x := old[l-1]
*h = old[:l-1]
return x
}

var dirs2290 = [][2]int{
{0, 1}, {1, 0}, {-1, 0}, {0, -1},
}

func Solution(grid [][]int) int {
m, n := len(grid), len(grid[0])
h := heap2290{{0, 0, 0}}
v := map[[2]int]int{
[2]int{0, 0}: 0,
}
for h.Len() > 0 {
cur := heap.Pop(&h).([3]int)
if cur[0] == m-1 && cur[1] == n-1 {
return cur[2]
}
for _, dir := range dirs2290 {
nx, ny := cur[0]+dir[0], cur[1]+dir[1]
if !(nx >= 0 && nx < m && ny >= 0 && ny < n) {
continue
}
need := cur[2] + grid[nx][ny]
key := [2]int{nx, ny}
//key = [3]int{nx, ny, need}
if vv, ok := v[key]; !ok || vv > need {
heap.Push(&h, [3]int{nx, ny, need})
v[key] = need
}
}
}
return -1
}
Original file line number Diff line number Diff line change
Expand Up @@ -10,12 +10,11 @@ func TestSolution(t *testing.T) {
// 测试用例
cases := []struct {
name string
inputs bool
expect bool
inputs [][]int
expect int
}{
{"TestCase", true, true},
{"TestCase", true, true},
{"TestCase", false, false},
{"TestCase1", [][]int{{0, 1, 1}, {1, 1, 0}, {1, 1, 0}}, 2},
{"TestCase2", [][]int{{0, 1, 0, 0, 0}, {0, 1, 0, 1, 0}, {0, 0, 0, 1, 0}}, 0},
}

// 开始测试
Expand All @@ -30,10 +29,10 @@ func TestSolution(t *testing.T) {
}
}

// 压力测试
// 压力测试
func BenchmarkSolution(b *testing.B) {
}

// 使用案列
// 使用案列
func ExampleSolution() {
}

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