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Scissors - Aida R. #54
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Nice work Aida, you hit the learning goals here. Well done. I left some minor comments, let me know what questions you have.
def grouped_anagrams(strings): | ||
""" This method will return an array of arrays. | ||
Each subarray will have strings which are anagrams of each other | ||
Time Complexity: ? | ||
Space Complexity: ? | ||
Time Complexity: O(n) | ||
Space Complexity: O(n) | ||
""" |
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👍 , Time/space are correct if the words are limited in length (like English words) Otherwise it would be O(n * m log m) where m is the length of each word.
def top_k_frequent_elements(nums, k): | ||
""" This method will return the k most common elements | ||
In the case of a tie it will select the first occuring element. | ||
Time Complexity: ? | ||
Space Complexity: ? | ||
Space Complexity: O(n) | ||
""" |
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👍 Because of the loop in lines 40-43, the time complexity is O(nk) because you have a loop going k times and each time finding the max element from the frequency map.
highest_value = max(freq_map, key=freq_map.get) | ||
result.append(highest_value) | ||
freq_map.pop(highest_value) | ||
return result | ||
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def valid_sudoku(table): |
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board
dictionary is not reset when checking the columns or subgrids.
Hash Table Practice
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